题解 | #字符串变形#
字符串变形
http://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
line = s.split(' ')
line=line[::-1]
s=""
for word in line:
word=word.swapcase()
s+=word
s+=" "
return s[0:n]