题解 | #字符串变形#
字符串变形
http://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
# write code here
# write code here
if s=="":
return ""
line = s.split(' ')
new =""
for i in line:
k=""
for j in i:
if j.isupper():
j = j.lower()
k = k + j
# print(j)
else:
j = j.upper()
k = k + j
# print(j)
new = k + " " + new
# print(new)
# print(len(new[0:n]))
return new[0:n]