题解 | #删除有序链表中重复的元素-I#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @return ListNode类
#
class Solution:
    def deleteDuplicates(self , head: ListNode) -> ListNode:
        # write code here
        if not head:
            return head
        s=set()
        while head:
            s.add(head.val)
            head=head.next
        s=list(s)
        s.sort()
        lend=cur=ListNode(s[0])
        for i in range(1,len(s)):
            cur.next=ListNode(s[i])
            cur=cur.next
        return lend