题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True: try: n = int(input()) val = input().split() k = int(input()) for i in range(len(val)): if i == len(val) - k and (k != 0): print(val[i]) if k == 0: print(0) except: break
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