题解 | #获取每个部门中当前员工薪水最高的相关信息#

当多人同时拥有最高薪水时直接用max(s.salary)无法查出

因此，用dense_rank分组排序，最高薪水相同的并列第一， t_rank=1

select dept_no,emp_no,salary from
	(select d.dept_no,s.emp_no,salary,
	dense_rank() over (partition by dept_no order by salary desc) as t_rank
	from dept_emp as d
	inner join salaries as s
	on d.emp_no=s.emp_no
	where d.to_date='9999-01-01' and s.to_date='9999-01-01') as a
where t_rank=1;

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