题解 | #删除字符串中出现次数最少的字符#

• 先遍历一次，对出现的字母进行计数
• 再遍历一次计数，得到最小次数
• 遍历字符串，对高于计数的进行输出

import java.util.Scanner;

/**
 * class com.sloera.nowcoder
 * user sloera
 * date 2022/2/23
 */
public class Main {
  public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    // 注意 hasNext 和 hasNextLine 的区别
    while (in.hasNextLine()) { // 注意 while 处理多个 case
      final String alphabet = in.nextLine();
      resolve(alphabet);
      System.out.println();
    }
  }

  private static void resolve(String alphabet) {
    int[] count = new int[26];
    for (int i = 0; i < alphabet.length(); i++) {
      count[alphabet.charAt(i)-'a']++;
    }
    int min = alphabet.length();
    for (int i = 0; i < count.length; i++) {
      if (count[i] > 0 && count[i] < min) {
        min = count[i];
      }
    }
    for (int i = 0; i < alphabet.length(); i++) {
      if (count[alphabet.charAt(i) - 'a'] > min) {
        System.out.print(alphabet.charAt(i));
      }
    }
  }

}