题解 | #学英语#

我就看看有谁的代码比我的长

while True:
    try:
        num = list(input().rjust(7,'0'))
        #构造个位、十位、百位词典
        dic0 = {'1':'one','2':'two','3':'three','4':'four', '5':'five', '6':'six', '7':'seven', '8':'eight', '9':'nine'}
        dic1 = {'2':'twenty','3':'thirty','4':'forty', '5':'fifty', '6':'sixty', '7':'seventy', '8':'eighty', '9':'ninety'}
        dic2 = {'0':'ten', '1':'eleven', '2':'twelve','3':'thirteen','4':'fourteen', '5':'fifteen', '6':'sixteen','7':'seventeen', '8':'eighteen', '9':'nineteen'}
        output = []
        #右起每3位一组，方便处理和最后链接
        mill = num[0:1]
        thou = num[1:4]
        base = num[4:8]
        #开关，用于判断十位为1时个位数字是否还单独输出
        k = True
        #判断是否加million
        if mill[0] != '0':
            output.append(dic0[mill[0]] + ' '+ 'million' + ' ')
        #中间3位
        if thou[0] != '0':
            if thou[1] == '0' and thou[2] == '0':
                output.append(dic0[thou[0]] + ' '+ 'hundred' + ' ')
            else:
                output.append(dic0[thou[0]] + ' '+ 'hundred' + ' ' + 'and' + ' ')
        if thou[1] != '0' and thou[1] != '1':
            output.append(dic1[thou[1]] + ' ')
        #当十位数字为1时，将开关k置为False，屏蔽个位数字输出
        if thou[1] == '1':
                output.append(dic2[thou[2]] + ' ')
                k = False
        if thou[2] != '0' and k :
            output.append(dic0[thou[2]] + ' ')
        #判断是否加thousand
        if thou[0] == '0' and thou[1] == '0' and thou[2] == '0':
                pass
        else:
            output.append('thousand' + ' ')
        #后3位,并将k重置
        k = True
        if base[0] != '0':
            if base[1] == '0' and base[2] == '0':
                output.append(dic0[base[0]] + ' '+ 'hundred' + ' ')
            else:
                output.append(dic0[base[0]] + ' '+ 'hundred' + ' ' + 'and'+ ' ')
        if base[1] != '0' and base[1] != '1':
            output.append(dic1[base[1]] + ' ')
        if base[1] == '1':
                output.append(dic2[base[2]] + ' ')
                k = False
        if base[2] != '0' and k :
            output.append(dic0[base[2]] + ' ')
        else:
            pass
        #列表转字符串
        final_output = ''
        for i in output:
            final_output += i
        print(final_output)
    except:
        break