HJ4 题解 | #字符串分隔#

思路：逐组处理，将一组字符串转化为char[]数组，8个字符一组放到新的char[]数组中，再将这个新的char[]数组转化为字符串输出。最后判断是否有剩余不够8个字符的一组，如果有，则补0，没有则不处理。

import java.util.*;

public class Main{
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        
        while(in.hasNext()){
            String str = in.next();
            char[] c = str.toCharArray();
            int len = str.length();
            int n = len / 8;
            
            for(int i = 0; i < n; i++){           //先处理个数够8的字符串
                char[] c2 = new char[8];
                for(int j = 0; j < 8; j++){
                    c2[j] = c[8*i+j];
                }
                String s2 = String.valueOf(c2);
                System.out.println(s2);
            }
            
            if(len % 8 != 0){                    //最后一组个数不够8的字符串补0
                int m = len % 8;
                char[] c3 = new char[8];
                for(int i = 0; i < m; i++){
                    c3[i] = c[8*n+i];
                }
                for(int i = m; i < 8; i++){
                    c3[i] = '0';
                }
                String s3 = String.valueOf(c3);
                System.out.println(s3);
            }
        }
    }
}

1. String转char[]数组：char[] c = str.toCharArray();
2. char[]数组转String：String str = String.valueOf(c);