题解 | #学英语#

输入数据小于2000000，所以热门大佬的代码可以简化

num1 = ['zero','one','two','three','four','five','six',
       'seven','eight','nine','ten','eleven','twelve',
       'thirteen','fourteen','fifteen','sixteen',
       'seventeen','eighteen','nineteen']
num2 = [0,0,'twenty','thirty','forty','fifty','sixty',
       'seventy','eighty','ninety']

# 100以内转英文
def n2w(n):
    if n > 0:
        if n < 20:
            word.append(num1[n])
        else:
            word.append(num2[n//10])
            if n%10 != 0:
                word.append(num1[n%10])

# 1000以内转英文
def hun(n):
    if n >= 100:
        word.append(num1[n//100])
        word.append('hundred')
        if n % 100 != 0:
            word.append('and')
    n2w(n%100)

while True:
    try:
        n = int(input())
    except:
        break
    else:
        word = []
        a = n % 1000  # 个十百位

        b = (n//1000) % 1000  # 个十百千
        c = n//1000000#个十百m

        if c > 0 :
            hun(c)
            word.append('million')
        if b > 0:
            hun(b)
            word.append('thousand')
        if a > 0 :
            hun(a)
        print(' '.join(word))