题解 | #字符串加解密#
字符串加解密
http://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
- 直接判断求解
while True:
try:
s1=input()
s2=input()
s1_new = ''
s2_new = ''
for i in s1:
if i.isupper():
if i == 'Z':
s1_new+='a'
else:
s1_new += chr(ord(i)+1).lower()
elif i.islower():
if i == 'z':
s1_new += 'A'
else:
s1_new += chr(ord(i)+1).upper()
elif i.isdigit():
s1_new += str(int(i)+1)[-1]
else:
s1_new += i
print(s1_new)
for i in s2:
if i.isupper():
if i == 'A':
s2_new +='z'
else:
s2_new += chr(ord(i) - 1).lower()
elif i.islower():
if i == 'a':
s2_new += 'Z'
else:
s2_new += chr(ord(i) - 1).upper()
elif i.isdigit():
if i == '0':
s2_new += '9'
else:
s2_new += str(int(i)-1)
else:
s2_new += i
print(s2_new)
except:
break
- 查表法
def check(a,b):
L1 = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
L2 = "BCDEFGHIJKLMNOPQRSTUVWXYZAbcdefghijklmnopqrstuvwxyza1234567890"
result = ""
if b == 1:
for i in a:
result += L2[L1.index(i)]
elif b == -1:
for i in a:
result += L1[L2.index(i)]
return result
while True:
try:
print(check(input(),1))
print(check(input(), -1))
except:
break
