题解 | #字符串字符匹配#
字符串字符匹配
http://www.nowcoder.com/practice/22fdeb9610ef426f9505e3ab60164c93
while True:
try:
a = list(input())
b = list(input())
len_a = len(a)
len_b = len(b)
if(len_a > len_b): #保证a始终是短的字符串
c = a
a = b
b = c
c = len_a
len_a = len_b
len_b = c
k = 0
flag = 0
for i in range(len_a):
for j in range(len_b):
if(a[i] == b[j]): #若a的字符在b中出现
flag += 1 #flag + 1
break
if(flag == len_a): #若都出现
print('true')
else:
print('false')
except:
break
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