题解 | #获得积分最多的人(一)#gary
获得积分最多的人(一)
http://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
from user u
right join (
select *, sum(grade_num) over(partition by user_id) grade_sum
from grade_info
order by grade_sum desc
limit 1
) x on x.user_id = u.id