题解 | #迷宫问题#

迷宫问题

http://www.nowcoder.com/practice/cf24906056f4488c9ddb132f317e03bc

#include<stdio.h>

int Ni, Mj;

typedef struct vint_ {
    int n;
    int dir;//which direction to the next pos
}vint;
vint tonext[5] = { {0,0}, {0,1}, {1,0}, {0,-1}, {-1,0} };//vint used as direction
vint map[10][10];

int ini(vint map[10][10], int* pi, int* pj, int d) {
    int leftd = d == 1 ? 4 : d - 1;
    int ni = *pi+tonext[leftd].n, nj =*pj+ tonext[leftd].dir;
    while (!(ni >= 0 && ni < Ni && nj>=0 && nj < Mj && map[ni][nj].n != 1)) {
        leftd=leftd == 4 ? 1 : leftd + 1;
        ni = *pi + tonext[leftd].n, nj = *pj + tonext[leftd].dir;
    }
    map[*pi][*pj].n = 2;
    map[*pi][*pj].dir = leftd;
    *pi =ni, * pj =nj;
    return leftd;
};

int main() {
    while (~scanf("%d %d", &Ni, &Mj)) {
        for (int i = 0; i < Ni; i++)
            for (int j = 0; j < Mj; j++) {
                scanf("%d", &map[i][j].n);
                //map[i][j].dir = -1;
            }
        int i = 0, j = 0, d = ini(map, &i, &j, 2);//d,previous pos to this one:E-1:S-2:W-3:N-4
        while (!(i == Ni - 1 && j == Mj - 1))
            d = ini(map, &i, &j, d);

        i = j = 0;
        while (!(i == Ni - 1 && j == Mj - 1)) {
            printf("(%d,%d)\n", i, j);
            int di = tonext[map[i][j].dir].n;
            int dj = tonext[map[i][j].dir].dir;
            i += di;
            j += dj;
        }
        printf("(%d,%d)\n", Ni - 1, Mj - 1);
    }
}

全部评论

相关推荐

喜欢走神的孤勇者练习时长两年半:池是池,发是发,我曾池,我现黑
点赞 评论 收藏
分享
点赞 收藏 评论
分享
牛客网
牛客企业服务