题解 | #字符串合并处理#

#include <stdio.h>
#include <string.h>

//读取，选择排序
//字典序列
//需要注意题目中用例会出现非A-F字母,原样输出即可
int main()
{
    char str1[101];
    char str2[101];
    char input[] = {"0123456789abcdefABCDEF"};
    char output[] = {"084C2A6E195D3B7F5D3B7F"};

    while (scanf("%s", str1) != EOF)
    {
        scanf("%s", str2);
        char str[202] = {'\0'};
        strcpy(str, str1);
        strcat(str, str2);
        int len = strlen(str);

        char temp;
        //按str[i]-'0'排序
        for (int i = 0; i < len; i += 2)
        {
            for (int j = i + 2; j < len; j += 2)
            {
                if (str[j] - '0' < str[i] - '0')
                {
                    temp = str[i];
                    str[i] = str[j];
                    str[j] = temp;
                }
            }
        }

        for (int i = 1; i < len; i += 2)
        {
            for (int j = i + 2; j < len; j += 2)
            {
                if (str[j] - '0' < str[i] - '0')
                {
                    temp = str[i];
                    str[i] = str[j];
                    str[j] = temp;
                }
            }
        }

        char outstr[202] = {'\0'};
        for (int i = 0; i < len; i++)
        {
            outstr[i]= str[i];
            for (int j = 0; j < 22; j++)
            {
                
                if (str[i] == input[j])
                    outstr[i] = output[j];
            }
        }

        printf("%s\n",outstr);

     }


    return 0;
}