题解- 数组 | #矩阵乘法#
矩阵乘法
http://www.nowcoder.com/practice/ebe941260f8c4210aa8c17e99cbc663b
while True:
try:
x = int(input())
y = int(input())
z = int(input())
x_y = [[0 for i in range(y)] for j in range(x)]
y_z = [[0 for i in range(z)] for j in range(y)]
result = [[0 for i in range(z)] for j in range(x)]
for i in range(x):
set_y = list(map(int,input().split()))
for j in range(y):
x_y[i][j]=set_y[j]
for i in range(y):
set_z = list(map(int, input().split()))
for j in range(z):
y_z[i][j]=set_z[j]
for i in range(x):
for j in range(z):
sum = 0
for k in range(y):
sum+=x_y[i][k]*y_z[k][j]
result[i][j]=sum
print(" ".join(list(map(str,result[i]))))
except:
break
好像无法插入numpy数据库，只能用循环一点点算了。一些常见的操作可以背下来，写代码会更快点：
- 将一次性输入的数据转化为数组：
set_x = list(map(int, input().split()))
- 将数组打印出来
print(" ".join(list(map(str,set_x))))
- 在python中用列表生成式来表示矩阵
[[0 for i in range(n)] for j in range(m)]
生成一个m*n 的矩阵
