题解 | #坐标移动#

笨人奔办法也是通过了 js

#include <string>
using namespace std;
void step(string s, int *x, int *y)
{
    int step;
    if (s[0] != 'A' && s[0] != 'S' && s[0] != 'W' && s[0] != 'D') //这里千万注意别用成了||
        return;
    if (s[1] < '0' || s[1] > '9')
        return;
    if (s.length() == 2)
        step = s[1] - '0';
    else if (s.length() == 3) {
        if (s[2] < '0' || s[2] > '9')
            return;
        step = (s[1] - '0') * 10 + (s[2] - '0');
    }
    switch(s[0]) {
        case 'A':
            *x -= step;
            break;
        case 'S':
            *y -= step;
            break;
        case 'W':
            *y += step;
            break;
        case 'D':
            *x += step;
            break;
    }
}
int main()
{
    int x = 0, y = 0, i = 0;
    string str, temp = "";
    cin >> str;
    for(; i < str.length(); i++) {
        if (str[i] != ';') {
            temp += str[i];
        } else {
            if (temp.length() > 1 && temp.length() <= 3) {
                step(temp, &x, &y);
            }
            temp.clear();
        }
    }
    cout << x << "," << y << endl;
}