题解 | #计算日期到天数转换#

int is_run(int year)
{
	if ((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0))
	{
		return 1;
	}
	return 0;
}

int main()
{
	int arr[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };//平年
	int year = 0;
	int month = 0;
	int day = 0;

	while (scanf("%d%d%d", &year, &month, &day) != EOF)
	{
		int sum = 0;
		int ret = is_run(year);
		if (month > 2)
		{
			sum+=ret;
		}
		int i = 0;
		for (i = 0; i < month-1; i++)
		{
			sum += arr[i];
		}
		sum += day;
		printf("%d\n", sum);
	}

	return 0;
}