题解 | #数值的整数次方#

class Solution {
public:
    double Power(double base, int exponent) {
        if(base==0&&exponent==0)
            return 0;
        if(exponent==0)
            return 1;
        else if(exponent>0)
        {
            double pow=1;
            while(exponent>0)
            {
                pow*=base;
                exponent--;
            }
            return pow;
        }
        else
        {
            exponent=(int)(-1*exponent);
            double pow=1;
            while(exponent>0)
            {
                pow*=base;
                exponent--;
            }
            pow=1/pow;
            return pow;
        }
    
    }
};