题解 | #合并两个排序的链表#
合并两个排序的链表
http://www.nowcoder.com/practice/d8b6b4358f774294a89de2a6ac4d9337
package main
import . "nc_tools"
/*
* type ListNode struct{
* Val int
* Next *ListNode
* }
*/
/**
*
* @param pHead1 ListNode类
* @param pHead2 ListNode类
* @return ListNode类
*/
func Merge( pHead1 *ListNode , pHead2 *ListNode ) *ListNode {
// write code here
cur1:= pHead1
cur2 := pHead2
resCur := &ListNode{}
resHead := resCur
for cur1 != nil && cur2 != nil {
if cur1.Val < cur2.Val {
resCur.Next = cur1
cur1 = cur1.Next
} else {
resCur.Next = cur2
cur2 = cur2.Next
}
resCur = resCur.Next
}
if cur1 != nil {
for cur1 != nil {
resCur.Next = cur1
cur1 = cur1.Next
resCur = resCur.Next
}
}
if cur2 != nil {
for cur2 != nil {
resCur.Next = cur2
cur2 = cur2.Next
resCur = resCur.Next
}
}
return resHead.Next
}