python3,re

'''
使用正则拿到ip和掩码
注意的点：
1.ip和掩码要同时考虑，是and的关系，一个有错就要加到error里面
2.我这里验证掩码的时候先转换成了二进制，注意是ob开头，注意要替换，而且还要补0
思路大概就是判断‘01’在不在掩码字符串里面
ps:这道题的筛选很粗糙，其实还可以更细致的筛选，题目用例没有作要求
'''

import re

def validate_hidden(res_ht):
    binary_ls = []
    for hidden_code in res_ht:
        binary = bin(int(hidden_code)).replace('0b','')
        if len(binary) < 8:
            binary += '0'*(8-len(binary)) + binary
            binary_ls.append(binary)
        else:
            binary_ls.append(binary)
    hidden_str = ''.join(binary_ls)
    if '01' in hidden_str:
        return False
            
    elif  '1' not in hidden_str or '0' not in hidden_str:
        return False
    return True

count_dic = {
    'A':0,
    'B':0,
    'C':0,
    'D':0,
    'E':0,
    'error':0,
    'private':0
}
while True:
    try:
        ip,hidden = input().split('~')
        res_hid = re.match('^(\d+).(\d+).(\d+).(\d+)$',hidden)
        res = re.match('^(\d+).(\d+).(\d+).(\d+)$',ip)
        if res_hid and res:
            pass
        else:
            count_dic['error'] += 1
            break
        
        res_t = res.groups()
        res_ht = res_hid.groups()

        hidden_result = validate_hidden(res_ht)
        if  1<=int(res_t[0])<=126:
            if hidden_result:
                if res_t[0] == '10':
                    count_dic['private'] += 1
                count_dic['A'] += 1
            else:
                count_dic['error'] += 1
        elif 128<=int(res_t[0])<=191:
            if hidden_result:
                if res_t[0] == '172' and 16<=int(res_t[1])<=31:
                    count_dic['private'] += 1
                count_dic['B'] += 1
            else:
                count_dic['error'] += 1
        elif 192<=int(res_t[0])<=223:
            if hidden_result:
                if res_t[0] == '192' and res_t[1]=='168':
                    count_dic['private'] += 1
                count_dic['C'] += 1
            else:
                count_dic['error'] += 1
        elif 224<=int(res_t[0])<=239:
            if hidden_result:
                count_dic['D'] += 1
            else:
                count_dic['error'] += 1
        elif 240<=int(res_t[0])<=255:
            if hidden_result:
                count_dic['E'] += 1
            else:
                count_dic['error'] += 1
        elif res_t[0]=='0' or res_t[0]=='127':
            continue
        else:
            count_dic['error'] += 1
       
    except:
        break

for value in count_dic.values():
    print(value,end=' ')