题解 | #创建动态数组#

#include<vector>
using namespace std;

int main() {

    int n;
    cin >> n;
    vector<int> result;
    int i;
    for(i=n;i<=2*n-1;i+=1){
        result.push_back(i);
    }
    
    for(i=n;i<=2*n-2;i+=1){
        printf("%d ",result[i-n]);
    }
    printf("%d\n",result[i-n]);
    // write your code here......
    

    return 0;
}