题解 | #删除链表的节点#

/*
 * function ListNode(x){
 *   this.val = x;
 *   this.next = null;
 * }
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @param val int整型 
 * @return ListNode类
 */
function deleteNode( head ,  val ) {
    // write code here
    let p = head;
    let pre  ;
    if(head.val === val){
        head = head.next;
        return head;
    }
    while(p.val !== val){
        pre = p;
        p=p.next;
    }
    pre.next = p.next;
    return head;
}
module.exports = {
    deleteNode : deleteNode
};