题解 | #截取字符串#
截取字符串
http://www.nowcoder.com/practice/a30bbc1a0aca4c27b86dd88868de4a4a
直接字符串切片即可
print(s[0:n])
pass
while True:
try:
s=str(input())
n=int(input())
func(s, n)
pass
except:
break