题解 | #SQL 6.近一个月发布的视频中热度最高的top3视频#

近一个月发布的视频中热度最高的top3视频

http://www.nowcoder.com/practice/0226c7b2541c41e59c3b8aec588b09ff

近一个月发布的视频中热度最高的top3视频

明确题意:

请找出近一个月发布的视频中热度最高的top3视频。

假设热度计算公式简化为:热度=(a*视频完播率+b*点赞数+c*评论数+d*转发数)*新鲜度;新鲜度=1/(最近无播放天数+1); 结果中热度保留为整数,并按热度降序排序。


问题分解:

  • 计算每个视频的各项指标:

    • 关联用户-视频互动记录和短视频信息表:JOIN tb_video_info USING(video_id);
    • 在每一行上追加当前日期列:
        LEFT JOIN (
            SELECT MAX(DATE(end_time)) as cur_date FROM tb_user_video_log
        ) as t_max_date ON 1
    
    • 按视频id分组:GROUP BY video_id
    • 计算各指标:
      • 播放进度:AVG(IF(TIMESTAMPDIFF(SECOND, start_time, end_time)>=duration, 1, 0)) as comp_play_rate
      • 点赞量:SUM(if_like) as like_cnt
      • 评论量:COUNT(comment_id) as comment_cnt
      • 转发量:SUM(if_retweet) as retweet_cnt
      • 最近被播放日期:MAX(DATE(end_time)) as recently_end_date
      • 发布日期:MAX(DATE(release_time)) as release_date
      • 当前日期(非分组列,加MAX避免语法错误):MAX(cur_date) as cur_date
    • 分组后筛选,筛选近30天的记录:HAVING TIMESTAMPDIFF(DAY, release_date, cur_date) < 30
  • 计算每个视频的热度:(100 * comp_play_rate + 5 * like_cnt + 3 * comment_cnt + 2 * retweet_cnt) / (TIMESTAMPDIFF(DAY, recently_end_date, cur_date) + 1) as hot_index

  • 保留为整数:ROUND(x, 0)

  • 取热度top3高的视频:ORDER BY hot_index DESC LIMIT 3


细节问题:

  • 表头重命名:as
  • 按热度倒序排序:ORDER BY hot_index

完整代码:

SELECT video_id,
    ROUND((100 * comp_play_rate + 5 * like_cnt + 3 * comment_cnt + 2 * retweet_cnt)
        / (TIMESTAMPDIFF(DAY, recently_end_date, cur_date) + 1), 0) as hot_index
FROM (
    SELECT video_id,
        AVG(IF(
            TIMESTAMPDIFF(SECOND, start_time, end_time)>=duration, 1, 0
        )) as comp_play_rate,
        SUM(if_like) as like_cnt,
        COUNT(comment_id) as comment_cnt,
        SUM(if_retweet) as retweet_cnt,
        MAX(DATE(end_time)) as recently_end_date,  -- 最近被播放日期
        MAX(DATE(release_time)) as release_date,  -- 发布日期
        MAX(cur_date) as cur_date  -- 非分组列,加MAX避免语法错误
    FROM tb_user_video_log
    JOIN tb_video_info USING(video_id)
    LEFT JOIN (
        SELECT MAX(DATE(end_time)) as cur_date FROM tb_user_video_log
    ) as t_max_date ON 1
    GROUP BY video_id
    HAVING TIMESTAMPDIFF(DAY, release_date, cur_date) < 30
) as t_video_info
ORDER BY hot_index DESC
LIMIT 3;
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全部评论
请问一下~ LEFT JOIN ( SELECT MAX(DATE(end_time)) as cur_date FROM tb_user_video_log ) as t_max_date ON 1 这里部分最后的ON 1是什么意思呀
1 回复 分享
发布于 2021-12-24 13:30
计算新鲜度的不能用timestampdiff,而应该用datediff。timestampdiff是计算时间差,然后四舍五入到day上,不是计算的日期差。
2 回复 分享
发布于 2023-05-07 13:42 北京
小红书
校招火热招聘中
官网直投
不用子查询,一次就可以。select t2.video_id, round((100*avg(if(timestampdiff(second,start_time,end_time)>=duration,1,0))+5*sum(if_like)+3*count(comment_id)+2*sum(if_retweet))/(datediff(cur_time,max(end_time))+1),0) as hot_index from tb_user_video_log as t1 join tb_video_info as t2 using(video_id) join (select max(end_time) as cur_time from tb_user_video_log) as t3 on 1 group by 1,release_time,cur_time having(datediff(cur_time,release_time)<30) order by 2 desc limit 3
1 回复 分享
发布于 2022-12-04 16:04 北京
为什么要left join 啊?有大佬解释下吗
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发布于 2022-03-18 21:41
having的执行顺序应该在select前面呀,release_date是在select后面定义的,这样写怎么也可以???
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发布于 2022-10-09 11:31 上海
一个用户能给一个视频点赞两次,6
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发布于 2022-12-16 11:01 湖南
请问大佬们,这里“MAX(cur_date) as cur_date -- 非分组列,加MAX避免语法错误”,为什么不加max会出错呢?
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发布于 2023-03-19 15:15 广东
"保留整数" 用floor()函数是不是更好些,向下取整,round是四舍五入
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发布于 04-16 19:21 上海

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