题解 | #成绩输入输出#
时间转换
http://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
int main()
{
long long seconds,min,hour,seco;
scanf("%d",&seconds);
hour=seconds/3600;
min=(seconds%3600)/60;
seco=(seconds%3600)%60;
printf("%ld %ld %ld",hour,min,seco);
return 0;
}