题解 | #合并两个排序的链表#
合并两个排序的链表
http://www.nowcoder.com/practice/d8b6b4358f774294a89de2a6ac4d9337
归并
ListNode* Merge(ListNode* pHead1, ListNode* pHead2)
{
ListNode *pNewHead = nullptr;
ListNode *pCurrent = nullptr;
while (pHead1 && pHead2)
{
if (pHead1->val > pHead2->val)
{
if (pNewHead)
{
pCurrent->next = pHead1;
pHead1 = pHead1->next;
pCurrent = pCurrent->next;
pCurrent->next = nullptr;
}
else
{
pNewHead = pHead1;
pHead1 = pHead1->next;
pNewHead->next = nullptr;
pCurrent = pNewHead;
}
}
else
{
if (pNewHead)
{
pCurrent->next = pHead2;
pHead2 = pHead2->next;
pCurrent = pCurrent->next;
pCurrent->next = nullptr;
}
else
{
pNewHead = pHead2;
pHead2 = pHead2->next;
pNewHead->next = nullptr;
pCurrent = pNewHead;
}
}
}
while (pHead1)
{
if (pNewHead)
{
pCurrent->next = pHead1;
pHead1 = pHead1->next;
pCurrent = pCurrent->next;
pCurrent->next = nullptr;
}
else
{
pNewHead = pHead1;
pHead1 = pHead1->next;
pNewHead->next = nullptr;
pCurrent = pNewHead;
}
}
while (pHead2)
{
if (pNewHead)
{
pCurrent->next = pHead2;
pHead2 = pHead2->next;
pCurrent = pCurrent->next;
pCurrent->next = nullptr;
}
else
{
pNewHead = pHead2;
pHead2 = pHead2->next;
pNewHead->next = nullptr;
pCurrent = pNewHead;
}
}
return pNewHead;
}