题解 | #删除链表的节点#
删除链表的节点
http://www.nowcoder.com/practice/f9f78ca89ad643c99701a7142bd59f5d
ListNode1* deleteNode(ListNode1* head, int val)
{
if (head->val == val)
{
head = head->next;
return head;
}
ListNode1 *pCurrentNode = head;
while (pCurrentNode->next)
{
if (pCurrentNode->next->val == val)
{
pCurrentNode->next = pCurrentNode->next->next;
}
pCurrentNode = pCurrentNode->next;
}
return head;
}
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