题解 | #走方格的方案数#
走方格的方案数
http://www.nowcoder.com/practice/e2a22f0305eb4f2f9846e7d644dba09b
感觉是一个迭代啊
def func(x,y):
if x < 0 or y < 0:
return 0
elif x == 0 or y == 0:
return 1
else:
return func(x-1, y)+func(x, y-1)
while True:
try:
a,b = map(int,input().split())
c = func(a, b)
print(c)
except:
break
