题解 | #从单向链表中删除指定值的节点#

while True:
    try:
        l = input().split()
        n = int(len(l[2:-1])/2 + 1)
        ll = [0]*n
        ll[0] = l[1]
        #         n = len(l[2:-1])/2 + 1
        # print(n)
        for i in range(2,len(l[2:]),2):
            ll.insert(ll.index(l[i+1])+1, l[i])
            #     print(ll)
        ll.remove(l[-1])
            # print(ll[0:int(n)-1])
        print(" ".join(ll[0:n-1]))
    except:
        break