题解 | #[NOIP2011]数字反转#

取模乘10

```#include<stdio.h>
int main ()
{
    int n=0;
    scanf("%d",&n);
    int i=0;
    int num=0;
    int sum=0;
    while(n!=0)
    {
        sum*=10;
        num=n%10;
        n=n/10;
        sum+=num;
    }
    printf("%d",sum);
    return 0;
}