题解 | #[NOIP2011]数字反转#
[NOIP2011]数字反转
https://ac.nowcoder.com/acm/problem/16584
取模乘10
```#include<stdio.h>
int main ()
{
int n=0;
scanf("%d",&n);
int i=0;
int num=0;
int sum=0;
while(n!=0)
{
sum*=10;
num=n%10;
n=n/10;
sum+=num;
}
printf("%d",sum);
return 0;
}
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