题解 | #寻找第K大#
寻找第K大
http://www.nowcoder.com/practice/e016ad9b7f0b45048c58a9f27ba618bf
public class Solution {
public int findKth(int[] a, int n, int K) {
// write code here
if(a == null ||a.length < 1){
return -1;
}
int left = 0;
int right = a.length - 1;
return part(a, left, right, K-1);
}
private int part(int[] data, int left, int right, int K){
int index = new Random().nextInt(right - left +1);
int value = data[index+left];
data[index+left] = data[left];
data[left] = value;
int lt = left;
int gt = right +1;
int i = left +1;
// left + 1 ... lt < value lt+1 ...i == value gt .. right > value
while(i < gt){
if(data[i] > value){
int temp = data[lt + 1];
data[lt +1] = data[i];
data[i] = temp;
lt ++;
i++;
}else if(data[i] < value){
int temp = data[gt-1];
data[gt -1] = data[i];
data[i] = temp;
gt --;
}else{
i++;
}
}
data[left] = data[lt];
data[lt] = value;
if(lt <= K && K < gt){
return data[K];
}
if(K < lt){
return part(data, left, lt -1, K);
}else{
return part(data, gt, right, K);
}
}
}