题解 | #求int型正整数在内存中存储时1的个数#

word = input('','s');
words = strsplit(word,';');
origenal = [0,0];
function [out] = islegal(in)
    if length(in) == 3
        if ~isempty(str2num(in(2:3)))
            out = 1;
            return;
        end
    end
    if length(in) == 2
        if ~isempty(str2num(in(2)))
            out = 1;
            return;
        end
    end
    out = 0;
end
function out = opp(in)
    p = in(1);
    q = str2num(in(2:end)); 
    out = [0,0];
    switch p
    case 'A'
         out = [-q,0];
    case 'S'
         out = [0,-q];
    case 'D'
         out = [q,0];
    case 'W'
         out = [0,q];
    otherwise 
         out = [0,0];
    end
end

for lop = 1:length(words)
    
    if islegal(words{lop})
        origenal = origenal+opp(words{lop});
    end
end

fprintf("%d,%d",origenal(1),origenal(2));