题解 | #质数因子#

【Python】双指针法

mystr=input()
str_len=len(mystr)
mystr=sorted(mystr)
i=j=0
count=0
while i<=j:
    for j in range(0,str_len):
        if(mystr[j]=='\n'):
            print(count)
            exit()
        elif mystr[i]!=mystr[j]:
            i=j
            count+=1
    break
print(count+1)