题解 | #二叉树的镜像#

typedef struct TreeNode Node;

struct TreeNode* Mirror(struct TreeNode* pRoot ) {
    Node* tmp = pRoot;
	Node* tmp1;

	if (!tmp)
		return NULL;

	tmp1 = tmp->left;
	tmp->left = tmp->right;
	tmp->right = tmp1;

	Mirror(pRoot->left);
	Mirror(pRoot->right);
    return tmp;
}