题解 | #二进制中1的个数#
二进制中1的个数
http://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8
class Solution {
public:
int NumberOf1(int n) {
int res = 0;
while(n) {
int x = n & (-n);
if(x) {
res++;
n = n - x;
}
}
return res;
}
};
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