题解 | #时间转换#

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int seconds;
    scanf("%d",&seconds);
    int h=0,m=0,s=0;
    h=seconds/3600;
    seconds-=h*3600;
    m=seconds/60;
    seconds-=m*60;
    s=seconds;
    printf("%d %d %d\n",h,m,s);
    return 0;
}