题解 | #查找组成一个偶数最接近的两个素数#

while(line = readline()) {
    let num = parseInt(line);
    // x + y = num && y - x = diff
    let diff;
    for (let i=0; i<= num/2; i++) {    //两个数差值最小为0，最大不会超过1/2，只要通过二元一次方程就能得出两个值，并保证为整数
        let x = (i + num) / 2;
        let y = (num - i) / 2;
        if (Math.floor(x) == x && Math.floor(y) == y) {
            if (isZhi(x)&&isZhi(y)) {
                diff = i;
                break;
            }
        }
    }
    let x = (diff + num) / 2;
    let y = (num - diff) / 2;
    print(y+'\n'+x)

    function isZhi(count) {
        let status = true;
        for (let i=2; i<=count/2; i++) {
            if (count%i == 0) {
                status = false;
            }
        }
        return status;
    } 
}