题解 | #数值的整数次方#

emmm

public class Solution {
    public double Power(double base, int exponent) {
        double basere=1;
        if(exponent < 0){
            for(int i =0;i<Math.abs(exponent);i++){
                basere = basere * (1/base);
            }
        }
        else{
            for(int i =0;i<Math.abs(exponent);i++){
                basere = basere * (base);
            }
        }
        return basere;
  }
}