题解 | #计算一元二次方程#

• 解题注意点：负数用实部和虚部合成，不要用complex，这个虚部的符号是j，不是i。。。。。

import math
lines=[]
while True:
    try:
        lines.append(input())
    except:
        break
for i in lines:
    a,b,c = list(map(float,i.split(' ')))
    if a == 0:
        print("Not quadratic equation")
    else:
        temp = b**2 - 4*a*c
        if temp == 0:
            x = -b/(2*a)
            print(f"x1=x2={x:.2f}")
        elif temp>0:
            x1 = -b/(2*a) - math.sqrt(temp) /(2*a)
            x2 = -b/(2*a) + math.sqrt(temp) /(2*a)
            print(f"x1={x1:.2f};x2={x2:.2f}")
        else:
            x = -b/(2*a)
            y =  math.sqrt(-temp) /(2*a)
            print(f"x1={x:.2f}-{y:.2f}i;x2={x:.2f}+{y:.2f}i")