题解 | #买卖股票的最好时机#
买卖股票的最好时机
http://www.nowcoder.com/practice/64b4262d4e6d4f6181cd45446a5821ec
# @param prices int整型一维数组 # @return int整型 class Solution: def maxProfit(self , prices):# -> int :List[int] # write code here profit,trade,i=0,0,0 k=len(prices)-2 if k <0: return 0 while i<=k: trade=max(prices[i+1:])-prices[i] profit=max(profit,trade) i+=1 return profit
更新一版,思路和上一版大体一致。都是利用max函数来实现。