题解 | #十六进制转十进制#
十六进制转十进制
http://www.nowcoder.com/practice/33e148570d5c4e728116e2f861638c9c
sumcc = 0
BoBo_list = ['A','B','C','D',"E","F"]
BoBo_list.reverse()
for count,i in enumerate(BoBo_list):
factor = 10+ord(i)-65
sumcc += pow(16,count)*factor
print("{:15d}".format(sumcc)) 
