题解 | #反转字符串#
反转字符串
http://www.nowcoder.com/practice/c3a6afee325e472386a1c4eb1ef987f3
/**
* 反转字符串
* @param str string字符串
* @return string字符串
*/
char* solve(char* str ) {
// write code here
char *p1=str;
char *p2=str;
int temp=0;
while (*p2!='\0')
{
p2++;
}
p2--;
while (p1<p2)
{
temp=*p1;
*p1=*p2;
*p2=temp;
p1++;
p2--;
}
return str;
} 
