题解 | #最长公共前缀#
最长公共前缀
http://www.nowcoder.com/practice/28eb3175488f4434a4a6207f6f484f47
# # # @param strs string字符串一维数组 # @return string字符串 # class Solution: def longestCommonPrefix(self , strs ): # write code here if len(strs) == 0: return "" l = "" m = strs[0] for index in range(len(m)): num = 1 for i in strs[1:]: if index < len(i): if m[index] == i[index]: num += 1 if num == len(strs): l += m[index] if num < len(strs): break return l