题解 | #矩阵的最小路径和#
矩阵的最小路径和
http://www.nowcoder.com/practice/7d21b6be4c6b429bb92d219341c4f8bb
# # # @param matrix int整型二维数组 the matrix # @return int整型 # class Solution: def minPathSum(self , matrix ): # write code here m = len(matrix) n = len(matrix[0]) temp = matrix for i in range(0, m): for j in range(0, n): if(i==0 and j==0): temp[i][j] = temp[i][j] elif i==0 and j>0: temp[i][j] += temp[i][j-1] elif j==0 and i>0: temp[i][j] += temp[i-1][j] else: temp[i][j] += min(temp[i-1][j],temp[i][j-1]) return temp[m-1][n-1]