题解 | #第一个只出现一次的字符#

找到重复字符串的位置

    def FirstNotRepeatingChar(self, s):
        # write code here
        if len(s) == 0:
            return  -1
        temp_list = []
        duplicate_index = []
        for i in range(len(s)):
            if s[i] not in temp_list:
                temp_list.append(s[i])
            else:
                duplicate_index.append(s[i])
        for i in range(len(s)):
            if s[i] not in duplicate_index:
                return i
        return  -1