题解 | #买卖股票的最好时机#
买卖股票的最好时机
http://www.nowcoder.com/practice/64b4262d4e6d4f6181cd45446a5821ec
class Solution:
def maxProfit(self , prices ):
# write code here
maxProfit = 0
n = len(prices)
for i in range(n-1):
for j in range(i+1,n):
profit = (prices[j]-prices[i])
if maxProfit < profit:
maxProfit = profit
return maxProfit
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