题解 | #井字棋#

#include<stdio.h>
char fun(char arr[3][3])
{
    int i = 0;
    int j = 0;
    int count = 0;
     for(i = 0; i < 3; i++)
    {
        j = 0;
        for(j = 0; j < 3; j++)
        {
            if(i == j)
            {
                count++;
                if(count == 3)
                {
                    return arr[i][j];
                }
            }
            if(arr[0][2] == arr[1][1] && arr[1][1] == arr[2][0])
            {
                return arr[0][2];
            }
            if(arr[i][0] == arr[i][1] && arr[i][1] == arr[i][2])
            {
                return arr[i][0];
            }
            if(arr[0][j] == arr[1][j] && arr[1][j] == arr[2][j])
            {
                return arr[0][j];
            }
        }
    }
     return -1;
}
int main()
{
    char arr[3][3];
    int i = 0;
    int j = 0;
    int num = 0;

    for(i = 0; i < 3; i++)
    {
        j = 0;
        for(j = 0; j < 3; j++)
        {
            scanf("%c ",&arr[i][j]);

        }
    }
    char ch = fun(arr);
    if(ch == 'K')
    {
        printf("KiKi wins!\n");
    }
    else if(ch == 'B')
    {
        printf("BoBo wins!\n");
    }
    else
    {
         printf("No winner!\n");
    }  
    return 0;
}