题解 | #用两个stack实现队列#

push：直接s1.append()
pop:若s2为空，则需要把s1中的元素pop到s2里；若s2不是空，则直接s2.pop

# -*- coding:utf-8 -*-
class Solution:
    def __init__(self):
        self.stack1 = []
        self.stack2 = []
    def push(self, node):
        # write code here
        self.stack1.append(node)
    def pop(self):
        # return xx
        if self.stack2:
            return self.stack2.pop()
        elif not self.stack1:
            return None
        else:
            while self.stack1:
                self.stack2.append(self.stack1.pop())
            return self.stack2.pop()