题解 | #数字颠倒#


//最傻的方法
#include<iostream>
#include<string>
using namespace std;
int main(){
string input;
cin>>input;
for(int i = 0; i<input.length();i++){
if('a'<=input[i] && input[i]<='z'){
if('a'<=input[i] && input[i]<='c') input[i] = '2';
else if('d'<=input[i] && input[i]<='f') input[i] = '3';
else if('g'<=input[i] && input[i]<='i') input[i] = '4';
else if('j'<=input[i] && input[i]<='l') input[i] = '5';
else if('m'<=input[i] && input[i]<='o') input[i] = '6';
else if('p'<=input[i] && input[i]<='s') input[i] = '7';
else if('t'<=input[i] && input[i]<='v') input[i] = '8';
else if('w'<=input[i] && input[i]<='z') input[i] = '9';</string></iostream>

    }
    else if('A'<=input[i] && input[i]<='Z'){
        if(input[i]!='Z'){
            input[i] +=33; 
        }
        else input[i] = 'a';
    }
}
cout<<input;
return 0;

}